SATHEE: Electromagnetic Induction

Electromagnetic Induction - Result Question 34

34. A 100 millihenry coil carries a current of $1 A$ .

Energy stored in its magnetic field is [1991]

(a) $0.5 J$

(b) $1 A$

(d) $0.1 J$

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Answer:

Correct Answer: 34. (c)

Solution:

(c) $E = \frac{1}{2} L i^{2} = \frac{1}{2} \times (100 \times 10^{- 3}) \times 1^{2} = 0.05 J$ In building a steady current in the circuit, the source emf has to do work against self inductance of coil and whatever energy consumed for tis work stored in magnetic field of coil-called magnetic potential energy (u) of coil $u = \frac{1}{2} L I^{2} = \frac{N ϕ i}{2}$

Electromagnetic Induction - Result Question 34

34. A 100 millihenry coil carries a current of $1 A$ .

Answer:

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Electromagnetic Induction - Result Question 34

34. A 100 millihenry coil carries a current of 1A.

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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34. A 100 millihenry coil carries a current of $1 A$ .