Electromagnetic Induction - Result Question 30
30. What is the self-inductance of a coil which produces $5 V$ when the current changes from 3 ampere to 2 ampere in one millisecond? [1993]
(a) 5000 henry
(b) 5 milli-henry
(c) 50 henry
(d) 5 henry
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Answer:
Correct Answer: 30. (b)
Solution:
(b) $L=\frac{e}{\frac{d i}{d t}}=\frac{e d t}{d i}=\frac{5 \times 10^{-3}}{(3-2)} H=5 mH$
