Electromagnetic Induction - Result Question 29

29. A varying current in a coil changes from 10A to zero in 0.5sec. If the average e.m.f induced in the coil is 220V, the self-inductance of the coil is

(a) 5H

(b) 6H

(c) 11H

(d) 12H

[1995]

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Answer:

Correct Answer: 29. (c)

Solution:

  1. (c) Initial current (I1)=10A; Final current (I2) =0; Time (t)=0.5sec and induced e.m.f. (ε)= 220V.

Induced e.m.f. ( (ε)

=LdIdt=L(I2I1)t=L(010)0.5=20L

or, L=22020=11H

[where L= Self inductance of coil]



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