Electromagnetic Induction - Result Question 28
28. A conductor of length $0.4 m$ is moving with a speed of $7 m / s$ perpendicular to a magnetic field of intensity $0.9 Wb / m^{2}$. The induced e.m.f. across the conductor is
(a) $1.26 V$
(b) $2.52 V$
(c) $5.04 V$
(d) $25.2 V$
[1995]
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Answer:
Correct Answer: 28. (b)
Solution:
- (b) Length of conductor $(l)=0.4 m$; Speed (v) $=7 m / s$ and magnetic field $(B)=0.9 Wb / m^{2}$. Induced e.m.f. $(V)=B l v \sin \theta=0.9 \times 0.4 \times 7 \times \sin$ $90^{\circ}=2.52 V$.
