Electromagnetic Induction - Result Question 28

28. A conductor of length 0.4m is moving with a speed of 7m/s perpendicular to a magnetic field of intensity 0.9Wb/m2. The induced e.m.f. across the conductor is

(a) 1.26V

(b) 2.52V

(c) 5.04V

(d) 25.2V

[1995]

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Answer:

Correct Answer: 28. (b)

Solution:

  1. (b) Length of conductor (l)=0.4m; Speed (v) =7m/s and magnetic field (B)=0.9Wb/m2. Induced e.m.f. (V)=Blvsinθ=0.9×0.4×7×sin 90=2.52V.


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