Electromagnetic Induction - Result Question 22
22. A long solenoid has 1000 turns. When a current of $4 A$ flows through it, the magnetic flux linked with each turn of the solenoid is $4 \times 10^{-3} Wb$. The self inductance of the solenoid is : [2016]
(a) $4 H$
(b) $3 H$
(c) $2 H$
(d) $1 H$
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Answer:
Correct Answer: 22. (d)
Solution:
- (d) Here, number of turns $n=1000$; current through the solenoid $i=4 A$; flux linked with each turn $=4 \times 10^{-3} Wb$
$\therefore$ Total flux linked,
$=1000[4 \times 10^{-3}]=4 Wb$
$\phi _{\text{total }}=4 \Rightarrow Li=4$
$\Rightarrow L=1 H$
Number of flux linkages with the coil $\propto$ current (I)
$ N \phi \propto I \Rightarrow N \phi=L_I \Rightarrow L=\frac{N \phi}{I} . $
