Electromagnetic Induction - Result Question 13
13. A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{p}(Wb / m^{2})$ in such a way that its axis makes an angle of $60^{\circ}$ with $\vec{B}$. The magnetic flux linked with the disc is:
[2008]
(a) $0.02 Wb$
(b) $0.06 Wb$
(c) $0.08 Wb$
(d) $0.01 Wb$
Show Answer
Answer:
Correct Answer: 13. (a)
Solution:
- (a) Here, $B=\frac{1}{p}(Wb / m^{2})$
$\theta=60^{\circ}$
Area normal to the plane of the disc
$=pr^{2} \cos 60^{\circ}=\frac{pr^{2}}{2}$
Flux $=B \times$ normal area
$=\frac{0.2^{\prime} 0.2}{2}=0.02 Wb$
