SATHEE: Electromagnetic Induction

Electromagnetic Induction - Result Question 1

1. A 800 turn coil of effective area $0.05 m^{2}$ is kept perpendicular to a magnetic field $510^{- 5}$ $T$ . When the plane of the coil is rotated by $90^{\circ}$ around any of its coplanar axis in $0.1 s$ , the emf induced in the coil will be :

(a) $2 V$

(b) $0.2 V$

(d) $0.02 V$

[2019]

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Solution:

(d) Given :

Magnetic field $B = 5 \times 10^{- 5} T$

Number of turns in coil $N = 800$

Area of coil A $= 0.05 m^{2}$

Time taken to rotate $= Δ t = 0.1 s$

Initial angle $θ_{1} = 0^{\circ}$

Final angle $θ_{2} = 90^{\circ}$

Change in magnetic flux $Δ ϕ$

$= N B A \cos 90^{\circ} - B A \cos 0^{\circ}$

$= - N B A$

$= - 800 \times 5 \times 10^{- 5} \times 0.05$

$= - 2 \times 10^{- 2}$ weber

$θ = - \frac{Δ ϕ}{Δ t} = \frac{- (-) 2 \times 10^{- 3} W b}{0.1 s} = 0.02 V$

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Electromagnetic Induction - Result Question 1

1. A 800 turn coil of effective area 0.05m2 is kept perpendicular to a magnetic field 510−5 T. When the plane of the coil is rotated by 90∘ around any of its coplanar axis in 0.1s, the emf induced in the coil will be :

Solution:

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1. A 800 turn coil of effective area $0.05 m^{2}$ is kept perpendicular to a magnetic field $510^{- 5}$ $T$ . When the plane of the coil is rotated by $90^{\circ}$ around any of its coplanar axis in $0.1 s$ , the emf induced in the coil will be :