SATHEE: Electric Charges and Fields

Electric Charges and Fields - Result Question 22

22. A thin conducting ring of radius $R$ is given a charge $+ Q$ . The electric field at the centre $O$ of the ring due to the charge on the part AKB of the ring is E. The electric field at the centre due to the charge on the part $A C D B$ of the ring is

[2008]

(a) E along $K O$

(b) E along OK

(d) 3 E along $O K$

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Answer:

Correct Answer: 22. (b)

Solution:

(b) By the symmetry of the figure, the electric fields at $O$ due to the portions $A C$ and $B D$ are equal in magnitude and opposite in direction. So, they cancel each other.

Similarly, the field at $O$ due to $C D$ and $A K B$ are equal in magnitude but opposite in direction. Therefore, the electric field at the centre due to the charge on the part $A C D B$ is $E$ along $O K$ .

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Electric Charges and Fields - Result Question 22

22. A thin conducting ring of radius R is given a charge +Q. The electric field at the centre O of the ring due to the charge on the part AKB of the ring is E. The electric field at the centre due to the charge on the part ACDB of the ring is

Answer:

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22. A thin conducting ring of radius $R$ is given a charge $+ Q$ . The electric field at the centre $O$ of the ring due to the charge on the part AKB of the ring is E. The electric field at the centre due to the charge on the part $A C D B$ of the ring is