Dual Nature of Radiation and Matter - Result Question 68
72. Momentum of a photon of wavelength $\lambda$ is
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======= ####72. Momentum of a photon of wavelength $\lambda$ is
c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $\frac{h}{\lambda}$
(b) zero
(c) $\frac{h \lambda}{c^{2}}$
(d) $\frac{h \lambda}{c}$
[1993]
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Answer:
Correct Answer: 72. (a)
Solution:
- (a) According to de Brogie wave equation,
$ \lambda=\frac{h}{m v}=\frac{h}{p} \quad \therefore p=\frac{h}{\lambda} $
