Dual Nature of Radiation and Matter - Result Question 66

70. When light of wavelength 300nm (nanometer) falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, however, light of 600nm wavelength is sufficient for creating photoemission. What is the ratio of the work functions of the two emitters?

[1993]

(a) 1:2

(b) 2:1

(c) 4:1

(d) 1:4

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Answer:

Correct Answer: 70. (b)

Solution:

(b) W0=hcλ0 or W01λ0;

W1W2=λ2λ1=600300=2



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