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======= ####41. The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function $5.01 e V$ , when ultraviolet light of $200 n m$ falls on it, must be:

c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $2.4 V$

(b) $- 1.2 V$

(d) $1.2 V$

[2010]

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Answer:

Correct Answer: 41. (b)

Solution:

(b) $K_{max} = \frac{h c}{λ} - W = \frac{h c}{λ} - 5.01$

$= \frac{12375}{λ (in \AA)} - 5.01$

$= \frac{12375}{2000} - 5.01 = 6.1875 - 5.01 = 1.17775$

$≃ 1.2 V$

The potential difference that must be applied to stop photoelectrons $= - 1.2 V$

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Dual Nature of Radiation and Matter - Result Question 39

41. The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01eV, when ultraviolet light of 200nm falls on it, must be:

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Answer:

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41. The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function $5.01 e V$ , when ultraviolet light of $200 n m$ falls on it, must be: