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======= ####37. Light of two different frequencies whose photons have energies $1 e V$ and $2.5 e V$ respectively illuminate a metallic surface whose work function is $0.5 e V$ successively. Ratio of maximum speeds of emitted electrons will be

c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $1 : 4$

(b) $1 : 2$

(d) $1 : 5$

[2011]

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Answer:

Correct Answer: 37. (b)

Solution:

(b) The maximum kinetic energy of emitted electrons is given by

$K . E = ϕ - ϕ_{0}$

$K . E_{1} = 1 e V - 0.5 e V = 0.5 e V$

$K . E_{2} = 2.5 e V - 0.5 e V = 2 e V$

$∴ \frac{K \cdot E_{1}}{K \cdot E_{2}} = \frac{0.5 e V}{2 e V} = \frac{1}{4}$

$\Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$

Dual Nature of Radiation and Matter - Result Question 35

37. Light of two different frequencies whose photons have energies $1 e V$ and $2.5 e V$ respectively illuminate a metallic surface whose work function is $0.5 e V$ successively. Ratio of maximum speeds of emitted electrons will be

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Answer:

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Dual Nature of Radiation and Matter - Result Question 35

37. Light of two different frequencies whose photons have energies 1eV and 2.5eV respectively illuminate a metallic surface whose work function is 0.5eV successively. Ratio of maximum speeds of emitted electrons will be

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Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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37. Light of two different frequencies whose photons have energies $1 e V$ and $2.5 e V$ respectively illuminate a metallic surface whose work function is $0.5 e V$ successively. Ratio of maximum speeds of emitted electrons will be