Dual Nature of Radiation and Matter - Result Question 2
2. An electron is accelerated through a potential difference of $10,000 V$. Its de Broglie wavelength is, (nearly): $(m_e=9 \quad 10^{-31} kg)$
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======= ####2. An electron is accelerated through a potential difference of $10,000 V$. Its de Broglie wavelength is, (nearly): $(m_e=9 \quad 10^{-31} kg)$
c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $12.210^{-13} m$
(b) $12.210^{-12} m$
(c) $12.210^{-14} m$
(d) $12.2 nm$
[2019]
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Answer:
Correct Answer: 2. (b)
Solution:
- (b) de-Broglie wavelength of electron
$ \lambda=\frac{12.27}{\sqrt{V}} \AA=\frac{12.27 \times 10^{-10}}{\sqrt{10000}}=12.27 \times 10^{-12} m $
