SATHEE: Current Electricity - Result Question 99

Current Electricity - Result Question 99

104. The resistance of the four arms P, Q, R and S in a Wheatstone’s bridge are $10 o h m, 30 o h m, 30$ ohm and $90 o h m$ , respectively. The e.m.f. and internal resistance of the cell are 7 volt and 5 ohm respectively. If the galvanometer resistance is $50 o h m$ , the current drawn from the cell will be

[2013]

(a) $0.2 A$

(b) $0.1 A$

(d) $1.0 A$

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Answer:

Correct Answer: 104. (a)

Solution:

(a) Given: $V = 7 V$

$\begin{aligned} R_{eq} = \frac{40 \times 120}{40 + 120} Ω \\ I = \frac{V}{R} = \frac{7}{5 + \frac{40 \times 120}{40 + 120}} \\ = \frac{7}{5 + 30} = \frac{1}{5} = 0.2 A . \end{aligned}$

Current Electricity - Result Question 99

Answer:

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Current Electricity - Result Question 99

104. The resistance of the four arms P, Q, R and S in a Wheatstone’s bridge are 10ohm,30ohm,30 ohm and 90ohm, respectively. The e.m.f. and internal resistance of the cell are 7 volt and 5 ohm respectively. If the galvanometer resistance is 50ohm, the current drawn from the cell will be

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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