Current Electricity - Result Question 98

103. A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery used across the potentiometer wire, has an emfof 2.0V and a negligible internal resistance. The potentiometer wire itself is 4m long, When the resistace R, connected across the given cell, has values of

(i) infinity (ii) 9.5Ω

The balancing lengths’, on the potentiometer wire are found to be 3m and 2.85m, respectively. The value of internal resistance of the cell is

[2014]

(a) 0.25Ω

(b) 0.95Ω

(c) 0.5Ω

(d) 0.75Ω

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Answer:

Correct Answer: 103. (c)

Solution:

  1. (c) Internal resistance of the cell,

r=(EVV)R=(122)R=(32.852.85)×(9.5)Ω=0.5Ω



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