SATHEE: Current Electricity - Result Question 91

Current Electricity - Result Question 91

96. The reading of an ideal voltmeter in the circuit shown is,

[NEET Odisha 2019]

(a) $0.4 V$

(b) $0.6 V$

(d) $0.5 V$

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Answer:

Correct Answer: 96. (a)

Solution:

(a) Current in first branch $= \frac{2}{50} A$

Current in second branch $= \frac{2}{50} A$

$Δ V$ from $A$ to $P$

$Δ V_{1} = 2 - \frac{2}{50} \times 20$

$Δ V$ from $A$ to $Q$

$Δ V_{2} = 2 - \frac{2}{50} \times 30$

$\Rightarrow$ Voltage difference $= 0.4 V$

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Current Electricity - Result Question 91

96. The reading of an ideal voltmeter in the circuit shown is,

Answer:

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