Current Electricity - Result Question 91
96. The reading of an ideal voltmeter in the circuit shown is,
[NEET Odisha 2019]
(a) $0.4 V$
(b) $0.6 V$
(c) $0 V$
(d) $0.5 V$
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Answer:
Correct Answer: 96. (a)
Solution:
- (a) Current in first branch $=\frac{2}{50} A$
Current in second branch $=\frac{2}{50} A$
$\Delta V$ from $A$ to $P$
$\Delta V_1=2-\frac{2}{50} \times 20$
$\Delta V$ from $A$ to $Q$
$\Delta V_2=2-\frac{2}{50} \times 30$
$\Rightarrow$ Voltage difference $=0.4 V$
