Current Electricity - Result Question 80

85. Two electric bulbs, one of $200 V, 40 W$ and other of $200 V, 100 W$ are connected in a domestic circuit. Then

[2000]

(a) they have equal resistance

(b) the resistance of $40 W$ bulb is more than $100 W$ bulb

(c) the resistance of $100 W$ bulb is more than $40 W$ bulb

(d) they have equal current through them

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Answer:

Correct Answer: 85. (b)

Solution:

(b) $\quad R_1=\frac{V^{2}}{P_1}=\frac{200 \times 200}{40}=1000 \Omega$

$R_2=\frac{V^{2}}{P_2}=\frac{200 \times 200}{100}=400 \Omega$

$\therefore R_1$ (for $.40 W)>R_2$ (for $100 W$ )



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