SATHEE: Current Electricity - Result Question 69

Current Electricity - Result Question 69

74. A current of $3 a m p$ flows through the $2 Ω$ resistor shown in the circuit. The power dissipated in the $5 - Ω$ resistor is:

(a) 4 watt

(b) 2 watt

(d) 5 watt

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Answer:

Correct Answer: 74. (d)

Solution:

(d) Clearly, $2 Ω, 4 Ω$ and ( $1 + 5) Ω$ resistors are in parallel. Hence, potential difference is same across each of them.

$∴ I_{1} \times 2 = I_{2} \times 4 = I_{3} \times 6$

Given $I_{1} = 3 A ∴ I_{1} \times 2 = I_{3} \times 6$

Given $I_{1} = 3 A$ .

$∴ I_{1} \times 2 = I_{3} \times 6$ provides

$I_{3} = \frac{I_{1} \times 2}{6} = \frac{3 \times 2}{6} = 1 A$ .

Now, the potential across the $5 Ω$ resistor is

$V = I_{3} \times 5 = 1 \times 5 = 5 V$ .

$∴$ the power dissipated in the $5 Ω$ resistor

$P = \frac{V^{2}}{R} = \frac{5^{2}}{5} = 5$ watt.

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Current Electricity - Result Question 69

74. A current of 3amp flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5−Ω resistor is:

Answer:

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74. A current of $3 a m p$ flows through the $2 Ω$ resistor shown in the circuit. The power dissipated in the $5 - Ω$ resistor is: