SATHEE: Current Electricity - Result Question 68

Current Electricity - Result Question 68

73. If power dissipated in the $9 - Ω$ resistor in the circuit shown is 36 watt, the potential difference across the $2 - Ω$ resistor is

[2011]

(a) 4 volt

(b) 8 volt

(d) 2 volt

Show Answer

Answer:

Correct Answer: 73. (c)

Solution:

$\Rightarrow 36 = \frac{V^{2}}{9}$

$\Rightarrow V = 18 V$

Current passing through the $9 Ω$ resistor is

$i_{1} = \frac{V}{R} = \frac{18}{9} = 2 A$

The $9 Ω$ and $6 Ω$ resistors are in parallel, therefore

$i_{1} = \frac{6}{9 + 6} \times i$

where $i$ is the current delivered by the battery.

$∴ i = \frac{2 \times 15}{6} = 5 A$

Thus, potential difference across $2 Ω$ resistor is $V = i R$

$= 5 \times 2$

$= 10 V$

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Current Electricity - Result Question 68

73. If power dissipated in the 9−Ω resistor in the circuit shown is 36 watt, the potential difference across the 2−Ω resistor is

Answer:

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73. If power dissipated in the $9 - Ω$ resistor in the circuit shown is 36 watt, the potential difference across the $2 - Ω$ resistor is