«««< HEAD

======= ####69. Two cities are $150 k m$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $k m$ is 8 volt and the average resistance per $k m$ is $0.5 Ω$ . The power loss in the wires is :

c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $19.2 W$

(b) $19.2 k W$

(d) $12.2 k W$

[2014]

Show Answer

Answer:

Correct Answer: 69. (b)

Solution:

(b) Total resistance $R = (0.5 Ω / k m) \times (150 k m)$ $= 75 Ω$

Total voltage drop $= (8 V / k m) \times (150 k m) = 1200 V$

Power loss $= \frac{(Δ V)^{2}}{R} = \frac{(1200)^{2}}{75} W$

$= 19200 W = 19.2 k W$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Current Electricity - Result Question 64

69. Two cities are 150km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8 volt and the average resistance per km is 0.5Ω. The power loss in the wires is :

«««< HEAD

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

69. Two cities are $150 k m$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $k m$ is 8 volt and the average resistance per $k m$ is $0.5 Ω$ . The power loss in the wires is :