SATHEE: Current Electricity - Result Question 47

Current Electricity - Result Question 47

50. The thermo e.m.f $E$ in volts of a certain thermocouple is found to vary with temperature difference $θ$ in $^{\circ} C$ between the two junctions according to the relation

[2010]

$E = 30 θ - \frac{θ^{2}}{15}$

The neutral temperature for the thermocouple will be

(a) $30^{\circ} C$

(b) $450^{\circ} C$

(d) $225^{\circ} C$

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Answer:

Correct Answer: 50. (d)

Solution:

(d) $E = 30 θ - \frac{θ^{2}}{15}$

For neutral temperature, $\frac{d E}{d θ} = 0$

$0 = 30 - \frac{2}{15} θ$

$∴ θ = 15 \times 15$

$= 225^{\circ} C$

Hence, neutral temperature is $225^{\circ} C$ .

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Current Electricity - Result Question 47

50. The thermo e.m.f E in volts of a certain thermocouple is found to vary with temperature difference θ in ∘C between the two junctions according to the relation

Answer:

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50. The thermo e.m.f $E$ in volts of a certain thermocouple is found to vary with temperature difference $θ$ in $^{\circ} C$ between the two junctions according to the relation