Current Electricity - Result Question 36

38. You are given several identical resistances each of value R=10Ω and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these resistances of 5Ω which can carry a current of 4 ampere. The minimum number of resistances of the type R that will be required for this job is

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======= ####38. You are given several identical resistances each of value R=10Ω and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these resistances of 5Ω which can carry a current of 4 ampere. The minimum number of resistances of the type R that will be required for this job is

c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) 4

(b) 10

(c) 8

(d) 20

[1990]

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Answer:

Correct Answer: 38. (c)

Solution:

  1. (c) To carry a current of 4 ampere, we need four paths, each carrying a current of one ampere. Let r be the resistance of each path. These are connected in parallel. Hence, their equivalent resistance will be r/4. According to the given

problem r4=5 or r=20Ω.

For this propose two resistances should be connected. There are four such combinations. Hence, the total number of resistance =4×2=8.



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