Current Electricity - Result Question 101

106. A potentiometer circuit is set up as shown. The potential gradient, across the potentiometer wire, is k volt /cm and the ammeter, present in the circuit, reads 1.0A when two way key is switched off. The balance points, when the key between the terminals (i) 1 and 2 (ii) 1 and 3, is plugged in, are found to be at lengths l1cm and l2cm respectively. The magnitudes, of the resistors R and X, in ohms, are then, equal, respectively, to

[2010]

(a) k(l2l1) and kl2

(b) kl1 and k(l2l1)

(c) k(l2l1) and kl1

(d) kl1 and kl2

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Answer:

Correct Answer: 106. (b)

Solution:

  1. (b) (i) When key between the terminals 1 and 2 is plugged in,

P.D. across R=IR=kl1

R=kl1 as I=1A

(ii) When key between terminals 1 and 3 is plugged in,

P.D. across(X+R)=I(X+R)=kl2

X+R=kl2

X=k(l2l1)

R=kl1 and X=k(l2l1)



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