SATHEE: Atoms - Result Question 33

Atoms - Result Question 33

35. The energy of hydrogen atom in nth orbit is $E_{n}$ , then the energy in nth orbit of single ionised helium atom will be

[2001]

(a) $4 E_{n}$

(b) $E_{n} / 4$

(d) $E_{n} / 2$

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Answer:

Correct Answer: 35. (a)

Solution:

(a) We have $E_{n} = \frac{- 2 π^{2} m K^{2} Z^{2} e^{4}}{n^{2} h^{2}}$ . For helium $Z = 2$ . Hence requisite answer is $4 E_{n}$

The energy required to ionise an atom is called ionisation energy. It is energy required to make the electron Jump from the present orbit to the infinite orbit.

$\begin{aligned} E_{ionisation} = E_{\infty} - E_{n} = 0 - (- 13.6 \frac{Z^{2}}{n^{2}}) \\ = + \frac{13.6 z^{2} e V}{n^{2}} \end{aligned}$

Atoms - Result Question 33

35. The energy of hydrogen atom in nth orbit is $E_{n}$ , then the energy in nth orbit of single ionised helium atom will be

Answer:

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Atoms - Result Question 33

35. The energy of hydrogen atom in nth orbit is En, then the energy in nth orbit of single ionised helium atom will be

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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35. The energy of hydrogen atom in nth orbit is $E_{n}$ , then the energy in nth orbit of single ionised helium atom will be