SATHEE: Atoms - Result Question 28

Atoms - Result Question 28

29. Ionization potential of hydrogen atom is $13.6 e V$ . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 e V$ . According to Bohr’s theory, the spectral lines emitted by hydrogen will be

(a) three

(b) Four

(d) Two

[2006]

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Answer:

Correct Answer: 29. (a)

Solution:

(a) Energy of ground state $13.6 e V$

Energy of first excited state

$= - \frac{13.6}{4} = - 3.4 e V$

Energy of second excited state

$= - \frac{13.6}{9} = - 1.5 e V$

Difference between ground state and 2nd excited state $= 13.6 - 1.5 = 12.1 e V$

So, electron can be excited upto 3rd orbit

No. of possible transition

$1 \to 2, 1 \to 3, 2 \to 3$

So, three lines are possible.

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Atoms - Result Question 28

29. Ionization potential of hydrogen atom is 13.6eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be

Answer:

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29. Ionization potential of hydrogen atom is $13.6 e V$ . Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 e V$ . According to Bohr’s theory, the spectral lines emitted by hydrogen will be