Atoms - Result Question 28
29. Ionization potential of hydrogen atom is $13.6 eV$. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy $12.1 eV$. According to Bohr’s theory, the spectral lines emitted by hydrogen will be
(a) three
(b) Four
(c) One
(d) Two
[2006]
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Answer:
Correct Answer: 29. (a)
Solution:
- (a) Energy of ground state $13.6 eV$
Energy of first excited state
$=-\frac{13.6}{4}=-3.4 eV$
Energy of second excited state
$=-\frac{13.6}{9}=-1.5 eV$
Difference between ground state and 2nd excited state $=13.6-1.5=12.1 eV$
So, electron can be excited upto 3rd orbit
No. of possible transition
$1 \to 2,1 \to 3,2 \to 3$
So, three lines are possible.
