Atoms - Result Question 26
27. The ground state energy of hydrogen atom is $13.6 eV$. When its electron is in the first excited state, its excitation energy is
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======= ####27. The ground state energy of hydrogen atom is $13.6 eV$. When its electron is in the first excited state, its excitation energy is
c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) $3.4 eV$
(b) $6.8 eV$
(c) $10.2 eV$
(d) 0
[2008]
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Answer:
Correct Answer: 27. (c)
Solution:
- (c) When the electron is in first excited state $(n=2)$, the excitation energy is given by
$\Delta E=E_2-E_1$
We have, $E_n=-\frac{13.6}{n^{2}} eV$
$\therefore E_2=-\frac{13.6}{2^{2}} eV=-3.4 eV$
Given $E_1=-13.6 eV$
$\therefore \Delta E=(-3.4)-(-13.6)=10.2 eV$.
