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======= ####23. An electron in the hydrogen atom jumps from excited state $n$ to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.75 e V$ . If the stopping potential of the photoelectron is $10 V$ , the value of $n$ is

c3eec34ec6b1fad69db54a20ad4b2dca40c2aa54 (a) 3

(b) 4

(d) 2

[2011M]

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Answer:

Correct Answer: 23. (b)

Solution:

(b) $K E_{max} = 10 e V$

$ϕ = 2.75 e V$

Total incident energy

$E = ϕ + K E_{max} = 12.75 e V$

$∴$ Energy is released when electron jumps from the excited state $n$ to the ground state.

$∵ E_{4} - E_{1} = - 0.85 - (- 13.6) e v$

$= 12.75 e V$

$∴$ value of $n = 4$

Atoms - Result Question 22

23. An electron in the hydrogen atom jumps from excited state $n$ to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.75 e V$ . If the stopping potential of the photoelectron is $10 V$ , the value of $n$ is

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Atoms - Result Question 22

23. An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75eV. If the stopping potential of the photoelectron is 10V, the value of n is

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Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

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Other Resources

Syllabus

Test Platform

Sample Mock Test

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NCERT Exercise Video Solution

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23. An electron in the hydrogen atom jumps from excited state $n$ to the ground state. The wavelength so emitted illuminates a photosensitive material having work function $2.75 e V$ . If the stopping potential of the photoelectron is $10 V$ , the value of $n$ is