Atoms - Result Question 19

20. An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be :

[2012]

(a) 24hR25m

(b) 25hR24m

(c) 25m24hR

(d) 24m25hR

( m is the mass of the electron, R, Rydberg constant and h Planck’s constant)

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Answer:

Correct Answer: 20. (a)

Solution:

  1. (a) For emission, the wave number of the radiation is given as

1λ=Rz2(1n121n22)

R= Rydberg constant, Z= atomic number

=R(112152)=R(1125)1λ=R2425

linear momentum

p=hλ=h×R×2425 (de-Broglie hypothesis)

mv=24hR25v=24hR25m



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