SATHEE: Alternating Current - Result Question 9

Alternating Current - Result Question 9

[1994]

(a) $I_{r m s} = \sqrt{2} I_{0}$

(b) $I_{rms} = π I_{0}$

(d) $I_{rms} = \frac{1}{\sqrt{2}} I_{0}$

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Answer:

Correct Answer: 9. (d)

Solution:

(d) $I_{r m s} = \frac{I_{0}}{\sqrt{2}}$

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Alternating Current - Result Question 9

9. In an a.c. circuit, the r.m.s. value of current, irms is related to the peak current, i0 by the relation

Answer:

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9. In an a.c. circuit, the r.m.s. value of current, $i_{r m s}$ is related to the peak current, $i_{0}$ by the relation