SATHEE: Alternating Current - Result Question 16

Alternating Current - Result Question 16

16. A resistance ’ $R$ ’ draws power ’ $P$ ’ when connected to an $A C$ source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes ’ $Z$ ‘, the power drawn will be

(a) $P \sqrt{\frac{R}{Z}}$

(b) $P (\frac{R}{Z})$

(d) $P (\frac{R}{Z})^{2}$

[2015]

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Answer:

Correct Answer: 16. (d)

Solution:

Pure resistor L-R series circuit

Phasor diagram

For pure resistor circuit, power

$P = \frac{V^{2}}{R} \Rightarrow V^{2} = P R$

For L-R series circuit, power

$P^{1} = \frac{V^{2}}{Z} \cos θ = \frac{V^{2}}{Z} \cdot \frac{R}{Z} = \frac{P R}{Z^{2}} \cdot R = P (\frac{R}{Z})^{2}$

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Alternating Current - Result Question 16

16. A resistance ’ R ’ draws power ’ P ’ when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes ’ Z ‘, the power drawn will be

Answer:

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16. A resistance ’ $R$ ’ draws power ’ $P$ ’ when connected to an $A C$ source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes ’ $Z$ ‘, the power drawn will be