Thermodynamics and Thermochemistry 1 Question 20

23. One mole of an ideal gas at 300 K in thermal contact with surroundings expands isothermally from 1.0 L to 2.0 L against a constant pressure of 3.0 atm.

In this process, the change in entropy of surroundings (ΔSsurr ) in JK1 is (1 L atm=101.3 J)

(2016 Adv.)

(a) 5.763

(b) 1.013

(c) -1.013

(d) -5.763

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Solution:

  1. By first law, ΔE=Q+W

For isothermal expansion, ΔE=0

Q=W Qirrev =Wirrev =pΔV=3(21)=3 L atm

Also, ΔSsurr =Qirrev T=(3×101.3)J300 K=303.9300=1.013JK1