SATHEE: The Solid State - Result Question 29

The Solid State - Result Question 29

####29. The second order Bragg diffraction of X-rays with $λ = 1.00 \AA$ from a set of parallel planes in a metal occurs at an angle $60^{\circ}$ . The distance between the scattering planes in the crystal is

(a) $0.575 \AA$

(b) $1.00 \AA$

(d) $1.15 \AA$

[1998]

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Solution:

(d) Given: Order of Bragg diffraction $(n) = 2$ ; Wavelength $(λ) = 1 \AA$ and angle $(θ) = 60^{\circ}$ . We know from the Bragg’s equation $n λ = 2 d \sin θ$

or $2 \times 1 = 2 d \sin 60^{\circ}$

$\Rightarrow 2 \times 1 = 2 . d . \frac{\sqrt{3}}{2} \Rightarrow d = \frac{2}{\sqrt{3}} = 1.15 \AA$

(where $d =$ difference between the scattering planes)

The Solid State - Result Question 29

Solution:

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The Solid State - Result Question 29

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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