SATHEE: The Solid State - Result Question 16

The Solid State - Result Question 16

####16. Structure of a mixed oxide is cubic close-packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal $A$ and the octahedral voids are occupied by a monovalent metal $B$ . The formula of the oxide is :

[2012 M]

(a) $A B O_{2}$

(b) $A_{2} B O_{2}$

(d) $A B_{2} O_{2}$

Show Answer

Solution:

(d) No. of $A^{2 +}$ ions $= \frac{1}{4} \times 8 = 2$

No. of $B^{+}$ ions $= 4 \times 1 = 4$

No. of atoms in $c c p$ ,

$O^{2 -} = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4$

Hence the formula of the oxide will be

$A_{2} B_{4} O_{4}$ or $A B_{2} O_{2}$ .

The Solid State - Result Question 16

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

The Solid State - Result Question 16

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu