The Solid State - Result Question 11
####11. A compound is formed by cation $C$ and anion $A$. The anions form hexagonal close packed ( $h c p$ ) lattice and the cations occupy $75 %$ of octahedral voids. The formula of the compound is:
[2019]
(a) $C_2 A_3$
(c) $C_3 A_4$
(b) $C_3 A_2$
(d) $C_4 A_3$
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Solution:
- (c)
Oh void (C) : $\quad HCP(A)$
$ \begin{matrix} \text{ No. of ions } \Rightarrow 6 \times \frac{75}{100} & : & 6 \\ \frac{3}{4} & : & 1 & \\ 3 & : & 4 & C_3 A_4 \end{matrix} $
