SATHEE: The Solid State - Result Question 10

The Solid State - Result Question 10

####10. An element has a body centered cubic (bcc) structure with a cell edge of $288 p m$ . The atomic radius is:

[2020]

(a) $\frac{\sqrt{2}}{4} \times 288 p m$

(b) $\frac{4}{\sqrt{3}} \times 288 p m$

(d) $\frac{\sqrt{3}}{4} \times 288 p m$

Show Answer

Solution:

(d) For bcc, $\sqrt{3} a = 4 r \Rightarrow r = \frac{\sqrt{3} a}{4}$

Given, $a = 288 p m$

$r = \frac{\sqrt{3}}{4} \times 288 p m$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

The Solid State - Result Question 10

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu