The Solid State - Result Question 10
####10. An element has a body centered cubic (bcc) structure with a cell edge of $288 pm$. The atomic radius is:
[2020]
(a) $\frac{\sqrt{2}}{4} \times 288 pm$
(b) $\frac{4}{\sqrt{3}} \times 288 pm$
(c) $\frac{4}{\sqrt{2}} \times 288 pm$
(d) $\frac{\sqrt{3}}{4} \times 288 pm$
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Solution:
- (d) For bcc, $\sqrt{3} a=4 r \Rightarrow r=\frac{\sqrt{3} a}{4}$
Given, $a=288 pm$
$r=\frac{\sqrt{3}}{4} \times 288 pm$
