SATHEE: The sBlock Elements - Result Question 41

The sBlock Elements - Result Question 41

####47. The compound $A$ on heating gives a colourless gas and a residue that is dissolved in water to obtain $B$ . Excess of $C O_{2}$ is bubbled through aqueous solution of $B, C$ is formed which is recovered in the solid form. Solid $C$ on gentle heating gives back $A$ . The compound is [2010]

(a) $C a S O_{4} \cdot 2 H_{2} O$

(b) $C a C O_{3}$

(d) $K_{2} C O_{3}$

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Solution:

(b) $C a C O_{3}$ (s) $\overset{Δ}{\to} C O_{2} (g) ↑ + C a O$ (s)

(A) colourless residue

$C a O (s) + H_{2} O ⟶ C a (O H)_{2}$

$C a (O H)_{2} + 2 C O_{2} + H_{2} O ⟶ C a (H C O_{3})_{2}$

$\underset{(C)}{C a (H C O_{3})_{2 (s)}} \to_{(A)}^{Δ} C a C O_{3 (s)} + C O_{2 (g)} + H_{2} O$

(b)

The given properties coincide with $C a C O_{3}$

The sBlock Elements - Result Question 41

Solution:

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The sBlock Elements - Result Question 41

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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