SATHEE: The sBlock Elements - Result Question 34

The sBlock Elements - Result Question 34

####40. All the following substances react with water. The pair that gives the same gaseous product is

[1994]

(a) $K$ and $K O_{2}$

(b) $N a$ and $N a_{2} O_{2}$

(c) $C a$ and $C a H_{2}$

(d) $B a$ and $B a O_{2}$

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Solution:

(c) $C a$ and $C a H_{2}$ both react with water to form $H_{2}$ gas,

$C a + 2 H_{2} O ⟶ C a (O H)_{2} + H_{2}$

$C a H_{2} + 2 H_{2} O ⟶ C a (O H)_{2} + 2 H_{2}$

whereas

$K$ gives $H_{2}$ while $K O_{2}$ gives $O_{2}$ and $H_{2} O_{2}$

$2 K + 2 H_{2} O ⟶ 2 K O H + H_{2}$

$2 K O_{2} + 2 H_{2} O ⟶ 2 K O H + O_{2} + H_{2} O_{2}$

$2 K O_{2} + 2 H_{2} O ⟶ 2 K O H + O_{2} + H_{2} O_{2}$

Similarly, Na gives $H_{2}$ while $N a_{2} O_{2}$ gives $H_{2} O_{2}$

$2 N a + 2 H_{2} O ⟶ 2 N a O H + H_{2}$

$N a_{2} O_{2} + 2 H_{2} O ⟶ 2 N a O H + H_{2} O_{2}$

Also, $B a$ gives $H_{2}$ while $B a O_{2}$ gives $H_{2} O_{2}$

$B a + 2 H_{2} O ⟶ B a (O H)_{2} + H_{2}$

$B a O_{2} + 2 H_{2} O ⟶ B a (O H)_{2} + H_{2} O_{2}$

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