SATHEE: The pBlock Elements - Result Question 2

The pBlock Elements - Result Question 2

####2. Aluminium chloride in acidified aqueous solution forms a complex ’ $A$ ‘, in which hybridisation state of $A l$ is ’ $B$ ‘. What are ’ $A$ ’ and ’ $B$ ‘, respectively?

[NEET Odisha 2019]

(a) $[A l (H_{2} O)_{6}]^{3 +}, d_{2} s p^{3}$

(b) $[A l (H_{2} O)_{6}]^{3 +}, s p^{3} d^{2}$

(d) $[A l (H_{2} O)_{4}]^{3 +}, d s p^{2}$

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Solution:

(b) $A l C l_{3} \overset{Acidified aq. sol.}{\to} [A l (H_{2} O)_{6}]^{3 +}$

(d) $M F_{6}^{3 -}$ $s p^{3} d^{2}$

Boron belongs to $2^{nd}$ period and it does not have vacant $d$ -orbital.

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The pBlock Elements - Result Question 2

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