The pBlock Elements - Result Question 2
####2. Aluminium chloride in acidified aqueous solution forms a complex ’ $A$ ‘, in which hybridisation state of $Al$ is ’ $B$ ‘. What are ’ $A$ ’ and ’ $B$ ‘, respectively?
[NEET Odisha 2019]
(a) $[Al(H_2 O)_6]^{3+}, d_2 s p^{3}$
(b) $[Al(H_2 O)_6]^{3+}, s p^{3} d^{2}$
(c) $[Al(H_2 O)_4]^{3+}, s p^{3}$
(d) $[Al(H_2 O)_4]^{3+}, d s p^{2}$
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Solution:
(b) $AlCl_3 \xrightarrow{\text{ Acidified aq. sol. }}[Al(H_2 O)_6]^{3+}$
(d) $MF_6^{3-}$ $s p^{3} d^{2}$
Boron belongs to $2^{\text{nd }}$ period and it does not have vacant $d$-orbital.
