SATHEE: The pBlock Elements - Result Question 17

The pBlock Elements - Result Question 17

####18. It is because of inability of $n s^{2}$ electrons of the valence shell to participate in bonding that:-

[2017]

(a) $S n^{2 +}$ is oxidising while $P b^{4 +}$ is reducing

(b) $S n^{2 +}$ and $P b^{2 +}$ are both oxidising and reducing

(d) $S n^{2 +}$ is reducing while $P b^{4 +}$ is oxidising

Show Answer

Solution:

(d) Due to inert pair effect, $P b$ (II) is more stable than $P b (I V)$

$S n (I V)$ is more stable than $S n$ (II)

$∴ P b (I V)$ is easily reduced to $P b (I I)$ and can acts as an oxidising agent whereas $S n$ (II) is easily oxidised to $S n (I V)$ and can acts as a reducing agent.

Inertness of $n s^{2}$ electrons of the valence shell to participate in bonding on moving down the group in heavier $p$ -block elements is called inert pair effect. It occurs due to poor shielding of the $n s^{2}$ electrons of the valence shell by the intervening $d$ and $f$ electrons.

The pBlock Elements - Result Question 17

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

The pBlock Elements - Result Question 17

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu