The P Block Elements - Result Question 91

####94. Identify the incorrect statement, regarding the molecule $XeO_4$ :

(a) $XeO_4$ molecule is tetrahedral

[NEET Kar. 2013]

(b) $XeO_4$ molecule is square planar

(c) There are four $p \pi-d \pi$ bonds

(d) There are four $s p^{3}-p, \sigma$ bonds

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Solution:

  1. (b)OW(O)(O)O

(Tetrahedral $s p^{3}$ )

$Xe$ : Ground state

$[Kr] 4 d^{10} 5 s^{2} 5 p^{6} 5 d^{0}$

$Xe:$ Excited state

$4 s p^{3}$ hybridised orbitals form 4 sigma bond with oxygen.



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