SATHEE: The P Block Elements - Result Question 79

The P Block Elements - Result Question 79

####82. A certain compound $(X)$ when treated with copper sulphate solution yields a brown precipitate. On adding hypo solution, the precipitate turns white. The compound is [1994]

(a) $K_{2} C O_{3}$

(b) $K I$

(d) $K_{3} P O_{4}$

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Solution:

(b) $K I$ reacts with $C u S O_{4}$ solution to produce cuprous iodide (white precipitate) and $I_{2}$ (which gives brown colour). Iodine reacts with hypo $(N a_{2} S_{2} O_{3} .5 H_{2} O)$ solution. Decolourisation of solution shows the appearance of white precipitate.

$\begin{aligned} 2 N a_{2} S_{2} O_{3} + I_{2} ⟶ \underset{\begin{array}{c} Sod. tetra \\ thionate \\ (colourless) \end{array}}{N a_{2} S_{4} O_{6} + 2 N a I} \end{aligned}$

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The P Block Elements - Result Question 79

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