The P Block Elements - Result Question 35
####35. When orthophosphoric acid is heated to $600^{\circ} C$, the product formed is
(a) $PH_3$
(b) $P_2 O_5$
(c) $H_3 PO_3$
(d) $HPO_3$
[1989]
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Solution:
(d) $\underset{\substack{\text{ orthophosphoric } \\ \text{ acid }}}{2 H_3 PO_4} \xrightarrow[-2 H_2 O]{60{ }^{\circ} C} \underset{\begin{matrix} \text{ metaphosphoric } \\ \text{ acid }\end{matrix} }{2 HPO_3}$
(c) $N_2 O_5+H_2 O \longrightarrow 2 HNO_3$
