####57. $K_2 Cr_2 O_7$ on heating with aqueous $NaOH$ gives
(a) $CrO_4^{2-}$
(b) $Cr(OH)_3$
(c) $Cr_2 O_7^{2-}$
(d) $Cr(OH)_2$
[1997]
$ K_2 CrO_4+Na_2 CrO_4+H_2 O $
Hence $CrO_4^{2-}$ ion is obtained.
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