SATHEE: The dand fblock elements

The dand fblock elements - Result Question 55

####55. An acidic solution of ’ $X$ ’ does not give precipitate on passing $H_{2} S$ through it. ’ $X$ ’ gives white precipitate when $N H_{4} O H$ is added to it. The white precipitate dissolves in excess of $N a O H$ solution. Pure ’ $X$ ’ fumes in air and dense white fumes are obtained when a glass rod dipped in $N H_{4} O H$ is put in the fumes. Compound ’ $X$ ’ can be [1999]

(a) $Z n C l_{2}$

(b) $F e C l_{3}$

(d) $S n C l_{2}$

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Solution:

(a) $X \overset{N H_{4} O H}{\to}$ White ppt

Given reactions (white precipitate with $H_{2} S$ in presence of $N H_{4} O H$ ) indicate that ’ $X$ ’ should be $Z n C l_{2}$ which explains all given reactions.

$Z n C l_{2}^{2} + 2 H_{2} O ⟶ Z n (O H)_{2} + 2 H C l ↑$

White fumes

$Z n (O H)_{2} \to_{Excess}^{2 N a O H} N a_{2} Z n O_{2} + 2 H_{2} O$

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The dand fblock elements - Result Question 55

Solution:

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