The dand fblock elements - Result Question 47
####47. $KMnO_4$ can be prepared from $K_2 MnO_4$ as per the reaction:
$3 MnO_4^{2-}+2 H_2 O \rightarrow$
$ 2 MnO_4^{-}+MnO_2+4 OH^{-} $
The reaction can go to completion by removing $OH^{-}$ions by adding.
[NEET 2013]
(a) $KOH$
(b) $CO_2$
(c) $SO_2$
(d) $HCl$
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Solution:
- (b) $HCl$ and $SO_2$ are reducing agents and can reduce $MnO_4^{-}$. $CO_2$ which is neither oxidising and nor reducing will provide only acidic medium. It can shift reaction in forward direction and reaction can go to completion.
