The dand fblock elements - Result Question 45
####45. In acidic medium, $H_2 O_2$ changes $Cr_2 O_7{ }^{-2}$ to $CrO_5$ which has two $(-O-O)$ bonds. Oxidation state of $Cr$ in $CrO_5$ is:-
(a) +5
(b) +3
(c) +6
(d) -10
[2014]
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Solution:
- (c) The structure of $CrO_5$ is
Hence, $CrO_5$ has two proxy linkage.
Now suppose the oxi. no. of $Cr$ is $x$ then $x+(-1 \times 4)+(-2)=0$
$\therefore \quad x=+6$
