SATHEE: The dand fblock elements

The dand fblock elements - Result Question 43

####43. Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified $K M n O_{4}$ for complete oxidation

[2015 RS]

(a) $F e S O_{4}$

(b) $F e S O_{3}$

(d) $F e (N O_{2})_{2}$

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Solution:

(a) Considering the same moles of compounds $F e^{2 +} S O_{4}^{2 -}$ only $F e^{2 +}$ is oxidised by $K M n O_{4}$ . $\overset{(+ 6)}{S O_{4}^{2 -}}$ in which sulphur is in highest oxidation state cannot be oxidised.

$\begin{aligned} F e^{2 +} S O_{3}^{2 -} \to_{(+ 6)}^{} F e^{3 +} \\ C O_{3}^{2 -} ⟶ S O_{4}^{2 -} + 2 e^{-} \end{aligned}$

Sulphur can be oxidised to (+6) i.e to $S O_{4}^{2 -}$

In $F e C_{2} O_{4} ⟶ F e^{3 +}$

Carbon can be oxidised to (+IV) i.e to $C O_{2}$

The dand fblock elements - Result Question 43

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The dand fblock elements - Result Question 43

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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