SATHEE: The dand fblock elements

The dand fblock elements - Result Question 21

####21. The correct order of decreasing second ionisation enthalpy of $T i (22), V (23), C r (24)$ and $M n (25)$ is :

[2008]

(a) $C r > M n > V > T i$

(b) $V > M n > C r > T i$

(d) $T i > V > C r > M n$

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Solution:

(a) $T i$ ; Z (22) is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{2}$

$V; Z (23)$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{3}$

$C r; Z (24)$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6} 4 s^{1}$

$M n; Z (25)$ is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 d^{5} 4 s^{2}$

The second electron in all the cases (except $C r$ ) is taken out from $4 s$ -orbital and for $C r$ it is taken from half-filled $3 d$ -orbital. The force required for removal of second electron will be more for $M n$ than others (except for $C r$ ) due to having more positive charge. Based on this, we find the

$Unknown environment 'tabular'$ \ \hline $=$ $Unknown environment 'tabular'$ & \ \hline \end{tabular} correct order $M n > V > T i$ .

i.e. $C r > M n > V >$ Ti.

The dand fblock elements - Result Question 21

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The dand fblock elements - Result Question 21

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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