Structure of Atom - Result Question 61
####65. Number of unpaired electrons in $N^{2+}$ is [1989]
(a) 2
(b) 0
(c) 1
(d) 34
Show Answer
Solution:
- (c) $N(7)=1 s^{2} 2 s^{2} 2 p^{3}$
$N^{2+}=1 s^{2}, 2 s^{2} 2 p_x^{1}$
Unpaired electrons $=1$.
####65. Number of unpaired electrons in $N^{2+}$ is [1989]
(a) 2
(b) 0
(c) 1
(d) 34
$N^{2+}=1 s^{2}, 2 s^{2} 2 p_x^{1}$
Unpaired electrons $=1$.
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