SATHEE: Structure of Atom - Result Question 6

Structure of Atom - Result Question 6

####6. The value of Planck’s constant is $6.63 \times 10^{- 34} J s$ . The velocity of light is $3.0 \times 10^{8} m s^{- 1}$ . Which value is closest to the wavelength in nanometers of a quantum of light with frequency of $8 \times 10^{15} s^{- 1}$ ?

(a) $3 \times 10^{7}$

(b) $2 \times 10^{- 25}$

(d) $4 \times 10^{1}$

[2003]

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Solution:

(d) $E = h v = \frac{h c}{λ}$ or $λ = \frac{c}{v}$

$\Rightarrow λ = \frac{3 \times 10^{8}}{8 \times 10^{15}} = 3.75 \times 10^{- 8} m$

In nanometer $λ = 3.75 \times 10$ which is closest to $4 \times 10^{1}$

Structure of Atom - Result Question 6

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Structure of Atom - Result Question 6

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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